Chemical shift table
| Type of carbon | δ / ppm |
|---|---|
| C–C (alkyl CH₃, CH₂, CH) | 5–40 |
| C–Cl, C–Br | 10–70 |
| C next to C=O (R–C–C=O) | 20–50 |
| C–N (amines) | 25–60 |
| C–O (alcohols, ethers, esters) | 50–90 |
| C=C (alkenes) | 90–150 |
| C≡N (nitriles) | 110–125 |
| Aromatic carbons | 110–160 |
| C=O in acids, esters and amides | 160–185 |
| C=O in aldehydes and ketones | 190–220 |
Ranges vary a little between data booklets. Use the one your exam board gives you.
How to read a spectrum
- Count the peaks. Each one is a different carbon environment. Fewer peaks than carbons means the molecule has symmetry.
- Look above 160 ppm for C=O. Above 190 is an aldehyde or ketone; 160–185 is an acid, ester or amide.
- Look at 110–160 for aromatic or alkene carbons, and 50–90 for carbons bonded to oxygen.
- Match the rest to alkyl carbons below 50 ppm.
In a normal (proton-decoupled) ¹³C spectrum every peak is a single line, and peak heights are not proportional to the number of carbons. Don't try to integrate them as you would in ¹H NMR.
Counting carbon environments
Worked example
C₃H₆O, three peaks at 7, 37 and 203 ppm. The peak above 190 ppm is an aldehyde or ketone C=O. Propanone would give only two peaks (it's symmetrical), so this must be propanal, CH₃CH₂CHO: three different carbons.
Combine ¹³C with ¹H NMR to get the full structure: see ¹H NMR splitting and the n+1 rule.
Quick answers
What does the number of peaks in a 13C NMR spectrum tell you?
Each peak is one carbon environment. The number of peaks is the number of different kinds of carbon, which is less than the total number of carbons if the molecule has symmetry.
Where does C=O appear in 13C NMR?
Aldehyde and ketone C=O carbons appear at about 190–220 ppm. Carboxylic acid, ester and amide C=O carbons appear at about 160–185 ppm.
Why are 13C NMR peaks not split?
Spectra are normally run proton-decoupled, so the coupling to hydrogens is removed and each carbon environment gives a single line.
Practise ¹³C NMR problems in BondlineFree, works offline, no account needed.
Open in Bondline